try to run demo on iphone 6 ios10 but it show linker error

check attached image

Hi Sallam,
Thank you for your question.

Please copy folder
CommunicationPackage/sdk/iphoneos/AvayaClientServices.framework
to CommunicationPackage/sdk/ and select targeted as "<connected_iPhone>" preferably.

see following article for details:
https://www.devconnectprogram.com/site/global/products_resources/avaya_client_sdk/programming_docs/current/ios/communication/guide/my_first_project.gsp

thanks it works well :D
now i have url configured by avaya to make video call it works well on pc browser and android browser but not work in ios browser cause ios not support webrtc
can i use your sdk to help us making video call

If you mean call without SIP enviroment, you can only join MeetMe conference using ClientSDK iOS. See the article https://www.devconnectprogram.com/site/global/products_resources/avaya_client_sdk/programming_docs/current/ios/communication/tech/over_the_top_conference_calls.gsp

If you mean call without SIP enviroment, you can only join MeetMe conference using ClientSDK iOS. See the article https://www.devconnectprogram.com/site/global/products_resources/avaya_client_sdk/programming_docs/current/ios/communication/tech/over_the_top_conference_calls.gsp

i don't have all the parameter of myMeetingInfo config i have only url that is work on browser

If your URL likes following

https://domain.com:8443/uwd/dist/index.html?audioOnly=false&brandingUrl=https:%2F%2Fdomain.com:8443%2Fportal%2Fcustom-styles%2F999&dataOnly=false&displayName=1&meetingId=123456789&middlewareUrl=https:%2F%2Fdomain.com:8443%2Fups%2Fresources%2Ftenants%2Fdefault%2Fmiddleware%2Fswc_info&oneTimeToken=bf39ced2-881f-4751-8w20-e26c0980c699&ottMode=true&sgHost=domain.com&sgPort=8443#!/

you can get this info from it

unifiedPortalUrl=https://domain.com:8443/portal/
meetingId=123456789

this link
https://test.org/api/call?patientId=45565&lang=en

You wont be able to make call using ClientSDK without setting configuration parameters for SIP or HTTP user agent.